The problem is, triangle ABC is an isosceles triangle where <B is it’s vertex angle. Given AB= x^2+2, BC=15, And AC=x. Find the value(s) Of x and determine each side length(s) Of the triangle.

Question

Not sure if I’ve done it right but I created a picture and set x^2+2x=15 then factored to get x=3, -5. I plugged the 3 back into x for x^2+2x to get AB=15, BC=15, And AC =3. Is this correct?

Answer 1

Looks right to me.

Answer 2

Thanks