a) .7 * .6 = ?
b) Which one does he lose?
Loses badminton = .3 * .6 = ?
Loses squash = .7 * .4 = ?
For "either-or" probability among the two above, add the newly found probabilities.
The probability that Richard beats John at badminto is 0.7. The probability that Richard beats John at sqaush is 0.6. These events are independant. Calculate the probabilty that, in a week when they play one game of badminton and sqaush:
a) Richard wins both games
b) Richard wins one game and loses the other.
1 answer