Asked by nabiha
The probability that Richard beats John at badminto is 0.7. The probability that Richard beats John at sqaush is 0.6. These events are independant. Calculate the probabilty that, in a week when they play one game of badminton and sqaush:
a) Richard wins both games
b) Richard wins one game and loses the other.
a) Richard wins both games
b) Richard wins one game and loses the other.
Answers
Answered by
PsyDAG
a) .7 * .6 = ?
b) Which one does he lose?
Loses badminton = .3 * .6 = ?
Loses squash = .7 * .4 = ?
For "either-or" probability among the two above, add the newly found probabilities.
b) Which one does he lose?
Loses badminton = .3 * .6 = ?
Loses squash = .7 * .4 = ?
For "either-or" probability among the two above, add the newly found probabilities.
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