.76 = e^-1.2 t
ln .76 = -1.2 t
just like your other problem
The probability P, as a percent, that a certain computer keyboard in a public library will last more than t years can be approximated by
P = 100e^−1.2t.
After how many years will the probability of keyboard failure be 76%? Round to the nearest tenth.
1 answer
1 answer