The probability of three independent events occurring are 1/2,1/3,1/4 respectively. What's the probability that only one of them will occur

Answer 1

Since A,B,C are independent, the chance that only A happens is P(A)*P(not B and not C) ...
So, P(only one event) is
1/2 * (2/3 * 3/4) + 1/3 * (1/2 + 3/4) + 1/4 * (1/2 * 2/3) = 3/4