Asked by Steve
The probability a company will hire a new employee is 0.38. Suppose three companies are randomly
selected.
(a) Find the probability all three companies will hire a new employee.
(b) Find the probability at least one company will hire a new employee.
(c) Find the probability none of the three companies will hire a new employee.
selected.
(a) Find the probability all three companies will hire a new employee.
(b) Find the probability at least one company will hire a new employee.
(c) Find the probability none of the three companies will hire a new employee.
Answers
Answered by
Damon
binomial distribution
p(n,k) = C(n,k)p^k (1-p)^(n-k)
p(3,1) = C(3,3) .38^3 * .62^0
= 1 * .38^3 * 1
do c next because b is 1 - c
p(3,0) = 1 * 1 * .68^3
now b = 1 - c
= 1 - .68^3
p(n,k) = C(n,k)p^k (1-p)^(n-k)
p(3,1) = C(3,3) .38^3 * .62^0
= 1 * .38^3 * 1
do c next because b is 1 - c
p(3,0) = 1 * 1 * .68^3
now b = 1 - c
= 1 - .68^3
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