Yes, if at constant temperature though.
p V = n R T
R is a constant
if T and n are constant then
p * V = constant call it k
p = k/V
126 = k/ 52
so
k = 52 * 126
then we expand it
p = k/168
p = 52 * 126 / 168
The pressure, p, of a gas varies inversely with its volume, v. Pressure is measured in units of pa. Suppose that a particular amount of a gas is initially at a pressure of 126 pa at a volume of 52L. If the volume is expanded to 168L, what will the new pressure be?
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