To calculate the pressure within the droplet, we can use the Laplace's law which states that the pressure inside a curved liquid droplet is greater than the pressure outside the droplet due to surface tension.
The formula for the pressure inside the droplet is given by:
P_inside = P_outside + (2 * surface tension) / radius
Where:
P_outside = 10^-32 N/cm^2 (pressure outside the droplet)
Surface tension = 0.0725 N
Radius = 0.021 mm = 0.0021 cm
Plugging in the values:
P_inside = 10^-32 + (2 * 0.0725) / 0.0021
P_inside = 10^-32 + 0.145 / 0.0021
P_inside = 10^-32 + 69.047
P_inside ≈ 69.047 N/cm^2
Therefore, the pressure within the droplet is approximately 69.047 N/cm^2.
The pressure outside the droplet of water dia 0.021 mm, is 10-32 n/cm square (at atmospheric pressure), calculate the pressure with in the droplet droplet if surface tention is given 0.0725 N
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