To solve this problem, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant.
Boyle's Law can be expressed as: P1V1 = P2V2
Where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.
We are given that the initial pressure is 70 kilopascals (P1 = 70 kPa), and the initial volume is 8.0 liters (V1 = 8.0 L). The final volume is given as 4.0 liters (V2 = 4.0 L).
By substituting these values into Boyle's Law, we can solve for the final pressure (P2):
P1V1 = P2V2
(70 kPa)(8.0 L) = P2(4.0 L)
560 kPa * L = 4.0 P2 * L
560 kPa = 4.0 P2
P2 = 560 kPa / 4.0
P2 = 140 kPa
Therefore, the pressure of the gas in the cylinder should be 140 kilopascals.
The pressure of gas in a cylinder is 70 kilopascals.
If the volume of the cylinder is reduced from 8.0 liters to 4.0 liters, what should be the pressure of the gas in the cylinder?
560 kilopascals
140 kilopascals
35 kilopascals
105 kilopascals
1 answer
1 answer