Assuming the amount of gas remains constant (i.e. no gas is added or removed), we can use the combined gas law to solve for the final volume:
(P1V1)/T1 = (P2V2)/T2
where P1 = initial pressure, V1 = initial volume, T1 = initial temperature, P2 = final pressure, V2 = final volume, and T2 = final temperature.
Plugging in the given values and solving for V2:
(100 kPa)(20 L)/(300 K) = (30 kPa)(V2)/(366 K)
V2 = (100 kPa)(20 L)(366 K)/(30 kPa)(300 K)
V2 ≈ 54.5 L
Therefore, the final volume is approximately 54.5 L. The answer is B.
The pressure of a sample of an inert gas reduced significantly from 100 kPa to 30kPa. The temperature increases from 27degreeC to 93degreeC. If the initial volume is 20 L, what is the final volume?
55 L
54.5 L
81 L
96 L
1 answer
1 answer