The pressure of a given mass of gas changes from 300Nm^-2 to 120Nm^-2 while the temperature drops from 127°c to -73°c.

The ratio of the final volume to the initial volume is?

1 answer

since PV = kT, PV/T = k remains constant. So,
300V1/(127+273) = 120V2/(-73+273)
Now just solve for V1/V2