The pressure of 6.0 L of an ideal gas in a flexible container is decreased to one-half of its original pressure, and its absolute temperature is decreased to one-seventh of the original. What is the final volume of the gas?

Answer 1

PV=nRT
v= nRT/P

It looks to me as t= 1/7 To and P is 1/2 Po

V= nRTo*2/7Po or volume is 2/7 of 6 liters.