Asked by Coffee
The pressure and volume of an ideal monatomic gas change from A to B to C. From A to B, volume remains 0.400 and pressure rises to 4.00x10^5. From B to C, volume changes from 0.400 to 0.200 while pressure remains the same. There is a curved line between A and C and is an isotherm.
Determine the total heat for the process.
I know ΔU=Q-W and W=PΔV=Q and that ΔV is -.200. But that's about it.
Determine the total heat for the process.
I know ΔU=Q-W and W=PΔV=Q and that ΔV is -.200. But that's about it.
Answers
Answered by
Coffee
Never mind. I figured it out.
A to B = 0 (no change in volume)
B to C = W=4.00e5*-.200 = -80000
-80000 + 0 = -80000
A to B = 0 (no change in volume)
B to C = W=4.00e5*-.200 = -80000
-80000 + 0 = -80000
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