The pressure and volume of an ideal monatomic gas change from A to B to C. From A to B, volume remains 0.400 and pressure rises to 4.00x10^5. From B to C, volume changes from 0.400 to 0.200 while pressure remains the same. There is a curved line between A and C and is an isotherm.

Determine the total heat for the process.

I know ΔU=Q-W and W=PΔV=Q and that ΔV is -.200. But that's about it.

1 answer

Never mind. I figured it out.

A to B = 0 (no change in volume)

B to C = W=4.00e5*-.200 = -80000

-80000 + 0 = -80000