2.48*10^5 Pascals
1 atm is 1 bar = 10^5 Pascals
so
2.48 bar
1860.15 is about 1860
It is NOT about 186 !!!!!!
You could say it is 1.86 * 10^3 though
The pressure 15.0 meters under water is 248 kPa.
what is this pressure in bar? (how would you set this up)
what is the pressure in torr?
I believe the second one is set up like this: 248 kpa * (760 torr/ 101.325 kpa)= 1860.15.. Although, if the lowest sig fig is 3, then would my answer be 1860 or 186?
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