To solve for \( 9^{-2} \), we can use the definition of negative exponents. Specifically, \( a^{-n} = \frac{1}{a^n} \).
So,
\[ 9^{-2} = \frac{1}{9^2} \]
Next, calculate \( 9^2 \):
\[ 9^2 = 81 \]
Now substitute back:
\[ 9^{-2} = \frac{1}{81} \]
This means the value of \( 9^{-2} \) is \( \frac{1}{81} \), which can also be written as "1 over 81."
Therefore, the correct response is:
1 over 81.