m g h = ½ m v²
h = v² / (2 g)
h = ½ g t² ... v² / (2 g) = ½ g t²
t = v / g .. this is ½ the flight time
The potential energy of a projectile at its maximum height is equal to its kinetic energy there . If the velocity of projection is 20m/s its time of flight is ?
2 answers
125