The potential difference between the accelerating plates of a TV set is about 30 kV. If the distance between the plates is 1.1 cm, find the magnitude of the uniform electric field in the region between the plates. (in N/C)

Answer 1

E = - grad φ
For 1D case
E = Δφ/d = 30000/0.011 = 2.73•10^-6 N/C

Answer 2

2.72*10^6