The position of a particle on the x-axis at time t, t > 0, is s(t) = ln(t) with t measured in seconds and s(t) measured in feet. What is the average velocity of the particle for 1 ≤ t ≤ e?

Question

a)1
b)e
c)e-1
d)1/(e-1)

Answer 1

s(1) = 0
s(e) = 1

so distance traveled in (e - 1) seconds is one foot
v = 1/(e-1) = .582 ft/s
d)

Answer 2

come on foo
answer the question