The position of a particle moving along the x axis is given by x = 6.0 t ^2 − 1.0 t^3, where x is in meters and t in seconds. What is the position of the particle when its acceleration is zero?

Answer 1

x = 6t^2 - t^3
v = 12t - 3t^2
a = 12-6t
so a(2) = 0
x(2) = ____