v = -3 t + 11
since v linear in t, find at t = 1 and at t = 4 and average
or alternatively
at t = 4
x = 13 + 44 - 24 = 33
at t = 1
x = 13 + 11 - 1.5 = 22.5
33-22.5 = 10.5 meters moved in 3 seconds
so average = 10.5/3 = 3.5 meters/second
or
find v at 2.5 = t = (1+4)/2
v = 11-3 t = 3.5 meters/s again :)
The position of a particle moving along the x-axis is given by
x = (13 + 11t − 1.5t2), where t is in seconds and x is in meters. What is the average velocity during the time interval from t = 1s to t = 4 s?
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