Asked by Anonymous
The position of a particle at any time t >= 0 is given by p(t) = -t^3 + t^2 + 5t + 3. What is the displacement of the particle during the first four seconds?
I think this is just p(4) - p(0) = -25 - 3 = -28.
I think this is just p(4) - p(0) = -25 - 3 = -28.
Answers
Answered by
Damon
yes
the displacement is the final position - the original position, a vector. It is not the total distance moved.
the displacement is the final position - the original position, a vector. It is not the total distance moved.
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