wow - what a lot of words. Just specify stuff with symbols, ok?
r(t) = (3t^3-2t)i + (5-2t^4)j
v(t) = (9t^2-1)i -8t^3 j
a(t) = 18t i - 24t^2 j
(d)
at t=3, dr/dt = v(3) = 26i-216j
so, tanθ = -216/26
The position ModifyingAbove r With right-arrow of a particle moving in an xy plane is given by ModifyingAbove r With right-arrow equals left-parenthesis 3 t cubed minus 2 t right-parenthesis ModifyingAbove i With caret plus left-parenthesis 5 minus 2 t Superscript 4 Baseline right-parenthesis ModifyingAbove j With caret with ModifyingAbove r With right-arrow in meters and t in seconds. In unit-vector notation, calculate
(a)ModifyingAbove r With right-arrow, (b)v Overscript right-arrow EndScripts, and (c)a Overscript right-arrow EndScripts for t = 3 s. (d) What is the angle between the positive direction of the x axis and a line tangent to the particle's path at t = 3 s? Give your answer in the range of (-180o; 180o).
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1 answer