The position function of an object moving along a straight line is given by s = f(t). The average velocity of the object over the time interval [a, b] is the average rate of change of f over [a, b]; its (instantaneous) velocity at t = a is the rate of change of f at a.
A ball is thrown straight up with an initial velocity of 112 ft/sec, so that its height (in feet) after t sec is given by s = f(t)=112t−16t^2.
(a) What is the average velocity of the ball over the following time intervals?
[3,4] ft/sec
[3,3.5] ft/sec
[3,3.1] ft/sec