To solve for t, we can substitute P(t) = 900 into the equation and solve for t:
900 = 1500 / (1 + 9e^(-0.6t))
1 + 9e^(-0.6t) = 1500 / 900
1 + 9e^(-0.6t) = 1.6667
9e^(-0.6t) = 0.6667
e^(-0.6t) = 0.0741
-0.6t = ln(0.0741)
t = ln(0.0741) / (-0.6)
t ≈ 6.9 years
Therefore, it will take approximately 6.9 years for the population to reach 900.
The population P of a fish farm in t years is modeled by the equation
P(t)=1500/1+9e-0.6t'
To the nearest tenth, how long will it take for the population to reach 900?
2 answers
impatient much?
Once is enough, thank you.
Repeated postings will not get faster or better responses.
Once is enough, thank you.
Repeated postings will not get faster or better responses.