#1 Po = 1000
Since P(1) = 1.8*P(0),
P(t) = 1000*1.8^t
To check this,
1000e^(k) = 1800
k = ln(1.8)
1000e^(ln(1.8)*t)
= 1000(e^(ln1.8))^t
= 1000*1.8^t
Or, if you prefer the base e,
P(t) = 1000e^(0.5878t)
I expect you can handle the rest, now, ok?
The population of a colony of mosquitoes grows exponentially according to the function
P(t) = P0ekt
1. If there are 1,000 mosquitoes initially and there are 1800 after 1 day, what is the size of the colony after 3 days?
2. How long will it take the colony to reach 10,000 mosquitoes?
please help i have a quiz on this soon. show all work
1 answer
1 answer