Asked by Kimber

The population in a 55 square mile city, City A, is 44,000. A neighboring city, City B, measures 65 square miles and has 48,750 citizens. Determine which city has a greater population density and by what percentage its population density is greater than the other city's.
I don't get how to do this. Please help!!
Answered by Ms. Sue
44,000 / 55 = 800 people per square mile

48,750 / 65 = 750 per square mile

800 - 750 = 50

50/44,000 = 0.0011 = 11%

Answered by Kimber
My teacher said the answer is 6.7% but I don't know how to get that
Answered by Damon
divide by density, not number of people
(50/750)100 = 6.67 %
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