The population in a 55 square mile city, City A, is 44,000. A neighboring city, City B, measures 65 square miles and has 48,750 citizens. Determine which city has a greater population density and by what percentage its population density is greater than the other city's.

Question

The population in a 55 square mile city, City A, is 44,000. A neighboring city, City B, measures 65 square miles and has 48,750 citizens. Determine which city has a greater population density and by what percentage its population density is greater than the other city's.
I don't get how to do this. Please help!!

Ms. Sue · Accepted Answer

44,000 / 55 = 800 people per square mile 48,750 / 65 = 750 per square mile 800 - 750 = 50 50/44,000 = 0.0011 = 11%

Kimber · Answer

My teacher said the answer is 6.7% but I don't know how to get that

Damon · Answer

divide by density, not number of people (50/750)100 = 6.67 %