The points A(1,5) and B(9,3) are part of a triangle ΔABC. The triangle has a right angle at A and and sides satisfy AB=2AC. Find a point C such that C lies above the line AB.

2 answers

Why did you repost all those questions again, they had all been answered

http://www.jiskha.com/display.cgi?id=1477910441
the slope of AB is -1/4
So, the slope of AC is 4

AB has length √68 = 2√17
So, AC has length √17 = √(1^2+4^2)

That means that C = A+(1,4) = (2,9)