Given: A(1,1) B(3,4), C(3,1).
a. (AB)^2 = (3-1)^2 + (4-1)^2 = 13
AB = sqrt13.
b. m = (4-1) / (3-1) = 3/2.
Y = mx + b
1 = (3/2)*1 + b
b = 1-3/2 = -1/2.
Eq: Y = (3/2)x - 1/2.
The points A=(1,1) B=(3,4) connects to point C (3,1).
a. Find the length of AB
b. The gradient and equation of line AB
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Henry
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