The point (x,-1) is 13 units from the point (3,11), What are the possible values of x ?

Answer 1

(x-3)^2 + (y-11)^2 = 13^2 = 169
y = -1

Solve those two equations simultaneously for x.

(x-3)^2 +(12) = 169
(x-3)^2 = 25
x - 3 = + or - 5
x = -2 or 8. y = -1 in both cases

Answer 2

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