The point of intersection of the diagonals of a rectangle is 4 cm further away from the smaller side than from the larger side of the rectangle. The perimeter of the rectangle is equal to 56 cm. Find the lengths of the sides of the rectangle.

Answer 1

Since the diagonals intersect halfway between the sides, we have the

width = 2x
length = 2(x+4)

Now use those to get the perimeter:

2(2x+2(x+4))=56

Solve for x, and then you are home free.

Answer 2

x=5