THE POINT (8,-3)LIES ON THE CURVE Y=3/(7-X) (a)IF Q IS THE POINT (x,3/(7-X)) USE YOUR CALCULATOR TO FIND THE SLOPE OF THE SECANT LINE PQ CORRECT TO SIX DECIMAL PLACES FOR THE VALUE OF X.

(i)7.9 Mpq?
(ii)7.99 mPQ?
(iii)7.999Mpq?
(iV)7.9999 MPQ?

1 answer

P = (8,-3)
The slope of PQ is

∆y/∆x = (3/(7-x)-(-3))/(x-8)
= (3+3(7-x))/((7-x)(x-8))
= (24-3x)/((7-x)(x-8))

You have provided no data about Q or the desired slope, but just plug in the numbers you have.