start with the equation
(x-2)^2 + (y-1)^2 = r^2
sub in the point (-4,3) to find r^2
The point (-4.3) lies on a circle whose center is at (2,1). Find an equation of this circle.
3 answers
Is the answer
(x-2)^2+(y-1)^2=40
(x-2)^2+(y-1)^2=40
correct