dy/dx = 4x*y^1/2
y^(-1/2) dy = 4x dx
2y^1/2 = 2x^2 + c
y^1/2 = x^2 + C
3 = 1 + C
C = 2
√y = x^2 + 2
now, what's your question?
the point (1,9) lies on the graph of an equation y=f(x) for which dy/dx=4x(sqrt(y)) where x is greater than or equal to 0 and y is greater than or equal to 0
a)6
b)4
c)2
d)sqrt(2)
e)0
1 answer