Length = L meters.
Width = (L-40) Meters.
L * (L-40) = 225m^2,
L^2 - 40L = 225,
L^2 - 40L - 225 = 0,
(L-5)(L+45) = 0,
The playing surface in the game of curling is a rectangular sheet of ice with an area of about 225 m^2. The width is about 40m less than the length. Find the approximate dimensions of the playing surface.
How would i solve this?
2 answers
Length = L meters.
Width = (L-40) Meters.
L * (L-40) = 225m^2,
L^2 - 40L = 225,
L^2 - 40L - 225 = 0,
(L+5)(L-45) = 0,
L+5 = 0,
L = -5.
L-45 = 0,
L=45.
Choose positive value of L:
L = 45m = Length.
Width = L-40 = 45-40 = 5m.
Width = (L-40) Meters.
L * (L-40) = 225m^2,
L^2 - 40L = 225,
L^2 - 40L - 225 = 0,
(L+5)(L-45) = 0,
L+5 = 0,
L = -5.
L-45 = 0,
L=45.
Choose positive value of L:
L = 45m = Length.
Width = L-40 = 45-40 = 5m.