The pilot travels 200 miles S at
20 deg.-20 min. When he changes direction, he makes a 90 deg angle
(20 deg.-20min.) + (69deg.-40 min.) =
90 Deg. During his return path, he completes the rt. triangle.
TanA = 200/148 = 1.3514, A = 53.5 deg.
B = 90 - 53.5 = 36.5 deg. = 36 Deg,30min.
Return Dir. = 36 Deg,30min - 20deg,20
=N 16deg.,10 min. W.
The pilot of an airplane left A and flew 200 miles in the direction S 20deg20mins W. He then turned and flew 148 miles in the direction S 69deg40mins E. If he now heads back to A, in what direction should he fly?
1 answer