the pilot of a private plane flies 20km in a direction 60 degrees north of east,then 30km straight east,then 10km straight north.how far and in what direction is the plane from the starting point

Answer 1

Disp. = 20km[60o] + 30km[0o] + 10km[90o].
Disp. = (20*Cos60+30) + (20*sin60+10)i.
Disp. = 40 + 27.3i = 48.5km[34.3o] N. of E.

Answer 2

I didn't get the whole process