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Find the value of xxx if A=2x, B=2x+10A=2x,\ B=2x+10A=2x, B=2x+10 and C=1x+8C=1x+8C=1x+8

x=x=x=

1 answer

To find the value of \( x \) based on the equations given:

  1. First equation: \( A = 2x \)
  2. Second equation: \( B = 2x + 10 \)
  3. Third equation: \( C = 1x + 8 \)

We can substitute for \( A \), \( B \), and \( C \) in terms of \( x \).

So we have:

  • \( A = 2x \)
  • \( B = 2x + 10 \)
  • \( C = x + 8 \)

Let's assume that \( A + B + C = 180^\circ \) if we are dealing with a triangle (it wasn't specified in the problem). Then we can write the equation:

\[ A + B + C = 180 \] Substituting the values of \( A \), \( B \), and \( C \):

\[ 2x + (2x + 10) + (x + 8) = 180 \]

Now, let's simplify this equation:

\[ 2x + 2x + 10 + x + 8 = 180 \]

Combine like terms:

\[ (2x + 2x + x) + (10 + 8) = 180 \] \[ 5x + 18 = 180 \]

Next, isolate \( x \):

\[ 5x = 180 - 18 \] \[ 5x = 162 \]

Now, divide both sides by 5:

\[ x = \frac{162}{5} = 32.4 \]

Thus, the value of \( x \) is:

\[ \boxed{32.4} \]

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