The physics of orbital radius and orbital period of a planet.

If a small planet were discovered whose orbital period was twice that of Earth, how many times farther from the sun would this planet be?

1 answer

Kepler: the ratio of the squares of the period is equal to the ratio of the cubes of the mean distances.

Period^2/1year= (radius/re)^3

2^2=4=(Radius/re)^3

radius= re*cubroot4