Asked by aly
The physics of orbital radius and orbital period of a planet.
If a small planet were discovered whose orbital period was twice that of Earth, how many times farther from the sun would this planet be?
If a small planet were discovered whose orbital period was twice that of Earth, how many times farther from the sun would this planet be?
Answers
Answered by
bobpursley
Kepler: the ratio of the squares of the period is equal to the ratio of the cubes of the mean distances.
Period^2/1year= (radius/re)^3
2^2=4=(Radius/re)^3
radius= re*cubroot4
Period^2/1year= (radius/re)^3
2^2=4=(Radius/re)^3
radius= re*cubroot4
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