The pH of pure water at 50 degrees celsius is 6.63. What is the value of Kw at 50 degrees celsius?

Answer 1

pH = -log(H^+)
-6.63 = log(H^+)
(H^+) = 2.34E-7
For pure water, H2O ==> H^+ + OH^-
Kw = (H^+)(OH^-)
Kw = (2.34E-7)(2,34E-7)