The pH of a 1 .00 x 10-2 M solution of cyanic acid(HOCN) is 2.77 at 25 degrees. Calculate Ka and pKa for HOCN from this result.

1 answer

...........HOCN ==> H^+ + OCN^-
I..........0.01.....0.......0
C..........-x.......x.......x
E........0.01-x.....x.......x

The problem tells you pH = 2.77; therefore, 2.77 = -log(H^+); therefore, (H^+) = 0.00170 = x in he above./
Evaluate H^+< OCN^-, and HOCN and calculate Ka.
pKa = -log K.
Similar Questions
  1. Cyanic Acid is a weak acidHOCN + H2O <--> H3O+ +OCN- ka= 3.5*10^-4 a) if 2.5ml of 0.01 M cyanic acid solution is added to 25.0
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. What is the concentration of hydrogen ionsin a solution containing 0.645 M HOCN (cyanic acid) and 0.235 M (NaOCN) (sodium
    1. answers icon 2 answers
    1. answers icon 1 answer
more similar questions