Question

The pH of a 0.55-M aqueous solution of hypobromous acid, HBrO, at 25°C is 4.48. What is the value of Ka for HBrO?

how do you solve for Ka?

Answer 1

HOBr ==> H^+ + OBr^-

Ka = (H^+)(OBr^-)/(HOBr)
Convert pH to H^+ and substitute into Ka expression. OBr^- is the same as H^+, substitute into Ka expression. HOBr = (0.55-H^+). Substitute into Ka expression. Solve for Ka.

Answer 2

2.0X 10^ -9