The pH of a 0.065 M solution of a weak base is 11.70. What is the value of Kb for this base?
5 answers
You're cheating on an assignment due for the class Chemistry 1012, your chemistry professor will be notified.
busted
awwkwaaaaard
they cant prove its you, plenty of people get the same problem, and finding help is not cheating....
-log(PH)=H
-log(POH)=OH
[OH][H]/[HA]=Ka
Kw=1*10^-14
Kw/Ka=Kb
those are the equations you need, just solve it... I don't see the cheating in help and I'M A TEACHER.
-log(PH)=H
-log(POH)=OH
[OH][H]/[HA]=Ka
Kw=1*10^-14
Kw/Ka=Kb
those are the equations you need, just solve it... I don't see the cheating in help and I'M A TEACHER.
That's why you just shouldn't use your real name
1 answer