figure the pH of a strong acid..
HX>>H + X
so pH= log (.0642)=1.2 which is considerably lower than 3.86. Probably not a strong acid. Lets look further.
work backwards.
concentration H= antilog 3.86
H=.00014
WEll, the acid is .00014/.0642 * 100 percent ionized, or .21 percent ionized.
check my work.
The pH of a 0.0642 M solution of a monoprotic acid
is 3.86. Is this a strong acid?
1 answer
1 answer