To find the frequency of a note, we can use the formula:
\[ \text{Frequency} (f) = \frac{1}{\text{Period} (T)} \]
Given that the period \( T = 4.85 \times 10^{-2} \) seconds, we can calculate the frequency as follows:
\[ f = \frac{1}{4.85 \times 10^{-2}} \text{ Hz} \]
Calculating this:
\[ f = \frac{1}{0.0485} \approx 20.6 \text{ Hz} \]
So the frequency of the note E0 is approximately 20.6 hertz.
Therefore, the correct answer is B. 20.6 hertz.