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The perimiter of a lot is 190 meters. The width is one-fourth of the length. Find the dimensions.

Here's my system of equations:

2w + 2L = 190
1/4L = w

What would I do from here? I prefer the elimination method. Would I multiply the second equation by 4? When I did so, it kind of messed up the equation.

Thanks! :)

3 answers

I would use substitution, but if you insist on using elimination, multiplying the second equation by 4 gives you
L = 4W or 4W - L = 0
now double that:
8W - 2L = 0 , now the first:
2W + 2L = 190, now add them
.
.
.

I'm sure you can finish it.
Did you get w = 19 and L = 76?

Thanks! :)
yes, correct!