the perimeter of the square is 204 ft. what is the value of x if 1 side of the square is 5x+6 ft

Answer 1

then
(5x+6)(5x+6) = 204
(5x+6)^2 = 204
5x+6 = ± √204 but x is sureley positive, so
x = (√204 - 6)/5 = (2√51 - 6)/5 or appr. 1.6567

Answer 2

204 / 4 = 51

5x + 6 = 51
5x = 45
x = ?

Answer 3

silly me, read the question wrong and made it harder than it had to be.