2(w + w+3.3) = 50
find w, the width, and then the length is w+3.3
The perimeter of the room is 50m. the length exceeds by the width by 3.3m. Find the length of the room.
2 answers
Find l and w, when the perimeter is 50m and the width exceeds the length by 3.3
w=x
l=x+3.3
2(x+x+3.3)=50
2x+2x+6.6=50
4x+6.6=50 (minus 6.6 on both sides)
4x=43.4 (devide 4 on both sides)
x=10.85
w=x
w=10.85m
l=x+3.3
l=10.85+3.3
l=14.15m
Therefore, the width is 10.85m and the length is 14.15m
w=x
l=x+3.3
2(x+x+3.3)=50
2x+2x+6.6=50
4x+6.6=50 (minus 6.6 on both sides)
4x=43.4 (devide 4 on both sides)
x=10.85
w=x
w=10.85m
l=x+3.3
l=10.85+3.3
l=14.15m
Therefore, the width is 10.85m and the length is 14.15m
2 answers