The perimeter of a square is 12cm greater than that of another square. It's area exceeds the area of the other by 39cm^2. Find the perimeter of each square. I don't get how to set this up.

Answer 1

let x be the side of the smaller square, area is x^2
then x+3 must be the side of the larger square.

(x+3)^2 -x^2=39
solve for x, and x+3