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The perimeter of a soccer field is 280yd. The width is 5yd more than half the length. Can you help me with the formula to solve this problem?

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P = 2L + 2W

280 = 2L + 2(0.5L + 5)

280 = 2L + L + 10

280 = 3L + 10

270 = 3L

90 = L

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