Let's denote the width of the tennis court as \( w \) feet. According to the problem, the length \( l \) of the tennis court is 6 feet longer than twice the width. Therefore, we can write the length as:
\[ l = 2w + 6 \]
We are also given that the perimeter of the tennis court is 228 feet. The formula for the perimeter \( P \) of a rectangle is given by:
\[ P = 2l + 2w \]
Substituting the given perimeter value:
\[ 228 = 2l + 2w \]
Now, substituting the expression for \( l \) into the perimeter equation:
\[ 228 = 2(2w + 6) + 2w \]
First, distribute the 2 inside the parentheses:
\[ 228 = 4w + 12 + 2w \]
Combine like terms:
\[ 228 = 6w + 12 \]
Subtract 12 from both sides to isolate the term with \( w \):
\[ 216 = 6w \]
Now, solve for \( w \) by dividing both sides by 6:
\[ w = \frac{216}{6} \]
\[ w = 36 \]
Therefore, the width of a regulation tennis court is 36 feet.
the perimeter of a regulation tennis court is 228 feet. If the length of a tennis court is 6 feet longer than twice the width, how wide is a regulation tennis court?
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