P = 2L + 2W
380 = 2(W + 10) + 2W
380 = 4W + 20
360 = 4W
90 = width
The perimeter of a rectangular field is 380 yd. The length is 10 yd longer than the width. Find the dimensions.
Please help and show work thank you
3 answers
The perimeter of a rectangular field is 380 yd. The length is 90 yd longer than the width. Find the dimensions.
The perimeter of a rectangular field is yd. The length is yd longer than the width. Find the dimensions.
The larger of the two sides is
nothing yd.
The larger of the two sides is
nothing yd.